Pages: [1]   Go Down
  Print  
Author Topic: Developer shows a jailbroken iPhone X on iOS 13.1.1 achieved by a new exploit  (Read 279 times)
HCK
Global Moderator
Hero Member
*****
Posts: 79425



« on: October 04, 2019, 04:05:21 pm »

Developer shows a jailbroken iPhone X on iOS 13.1.1 achieved by a new exploit

<div class="feat-image"></div>
<p>Developer and hacker Axi0mX recently shared a new exploit called “checkm8” that offers the possibility to jailbreak almost every Apple A-series CPU up to A11 Bionic chip. Today, the developer has posted a video that shows an iPhone X (which runs on A11 chip) booting up in verbose mode — something that is only possible with more profound modifications to the core of the system.</p>
<p> <a href="https://9to5mac.com/2019/09/29/iphone-x-jailbreak/#more-612847" class="more-link">more…[/url]</p>
<p>The post <a rel="nofollow" href="https://9to5mac.com/2019/09/29/iphone-x-jailbreak/">Developer shows a jailbroken iPhone X on iOS 13.1.1 achieved by a new exploit[/url] appeared first on <a rel="nofollow" href="https://9to5mac.com">9to5Mac[/url].</p><div class="feedflare">
<img src="[url]http://feeds.feedburner.com/~ff/9To5Mac-MacAllDay?i=amKG3V-hyxk:GdoDxyxF5m0:D7DqB2pKExk" border="0"></img>[/url]
</div><img src="http://feeds.feedburner.com/~r/9To5Mac-MacAllDay/~4/amKG3V-hyxk" height="1" width="1" alt=""/>

Source: Developer shows a jailbroken iPhone X on iOS 13.1.1 achieved by a new exploit
Logged
Pages: [1]   Go Up
  Print  
 
Jump to: